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Question #41508

Difficulty: 8/10 | 🟢 Free

The Question

Let Ik=∫0π/2∑r=02k(kr)(sin⁡2rxsin⁡2rx+cos⁡2rx+rk)dxI_k = \int_0^{\pi/2} \sum_{r=0}^{2k} \binom{k}{r} \left( \frac{\sin^{2r} x}{\sin^{2r} x + \cos^{2r} x} + \frac{r}{k} \right) dx for k∈Nk \in \mathbb{N}. Evaluate the limit: L=lim⁡n→∞1n2ln⁡(∏k=1n2πIk)L = \lim_{n \to \infty} \frac{1}{n^2} \ln \left( \prod_{k=1}^n \frac{2}{\pi} I_k \right)

Options

  • A.

    ln⁡2\ln 2

  • B.

    ln⁡22\frac{\ln 2}{2}

  • C.

    2ln⁡22 \ln 2

  • D.

    0

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

Definite Integral Properties (King's Property)|Binomial Coefficient Summation Properties|The Empty Set Trap|The L'Hôpital's Rule Misuse

Why This Question Is Tricky

Common Mistakes

This question tests the integration of binomial series using King's Property while embedding two lethal traps.

The 'Empty Set Trap' is triggered by the summation limit 2k2k; students who mechanistically apply summation formulas without realizing (kr)=0\binom{k}{r} = 0 for r>kr > k will incorrectly evaluate the series (e.g., assuming the sum yields 22k2^{2k}), leading to an incorrect limit of ln⁡2\ln 2.

The 'L'Hôpital's Rule Misuse' trap targets students who see the ∞/∞\infty/\infty limit and attempt to differentiate the product of integrals with respect to nn.

Since nn is discrete and embedded in the binomial upper limits, continuous differentiation is mathematically invalid and practically impossible, forcing the student to first evaluate the series symmetry and the definite integral to a constant expression before taking the limit.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterIntegrals - Class 12
ConceptDefinite Integral Properties (King's Property)
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree