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Question #41507
The Question
Let be the solution to the differential equation for , satisfying the initial condition . Find the value of .
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Specialist
Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.
Concepts Behind This Question
Completing the Square in Quadratics|Substitution Logic in Homogeneous DE|Implicit to Explicit Conversion
Why This Question Is Tricky
Common Mistakes
This question tests the student's ability to navigate the implicit to explicit conversion trap after solving a homogeneous differential equation.
By using the substitution y=vx, the integral naturally leads to a quadratic in v, requiring completing the square.
The critical filter occurs when taking the square root of (v+1)^2: students frequently default to the principal (positive) root.
However, the initial condition y(1) = -3 strictly demands the negative branch.
Failing to verify the branch selection leads directly to the trap answer 3e^6.
Quick Facts About This Question
Question Information
| Subject | Mathematics |
| Chapter | Integrals - Class 12 |
| Concept | Completing the Square in Quadratics |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |