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Question #41449

Difficulty: 8/10 | 🟢 Free

The Question

A discrete random variable XnX_n takes values k∈{1,2,…,2n}k \in \{1, 2, \dots, 2n\}. A transformed random variable is defined as Un=Xn−nnU_n = \frac{X_n - n}{n}. The probability mass function of XnX_n is given by P(Xn=k)=1Zn(uk+1)2cos⁡(π2uk)P(X_n = k) = \frac{1}{Z_n} (u_k + 1)^2 \cos\left( \frac{\pi}{2} u_k \right) where uk=k−nnu_k = \frac{k - n}{n} and ZnZ_n is the normalization constant. Evaluate lim⁡n→∞E[Un]\lim_{n \to \infty} E[U_n].

Options

  • A.

    π2−8π2−4\frac{\pi^2 - 8}{\pi^2 - 4}

  • B.

    π2−4π2−8\frac{\pi^2 - 4}{\pi^2 - 8}

  • C.

    π2−8π2+4\frac{\pi^2 - 8}{\pi^2 + 4}

  • D.

    2π2−16π2−4\frac{2\pi^2 - 16}{\pi^2 - 4}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Monster

Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.

Concepts Behind This Question

Integral as the Limit of a Sum|Probability Mass Function (PMF)|Step-Deviation Method (u = (x-a)/h)

Why This Question Is Tricky

Common Mistakes

This question bridges probability and calculus by requiring the evaluation of an expectation as the limit of a Riemann sum.

The core trap lies in the step-deviation substitution uk=(k−n)/nu_k = (k-n)/n.

Students often struggle to correctly map the discrete summation limits (k=1k=1 to 2n2n) to the continuous integral bounds (u=−1u=-1 to 11) and fail to recognize Δu=1/n\Delta u = 1/n as the differential dudu.

A common mistake is expanding the sum in terms of x=k/nx = k/n and integrating from 00 to 22, which bypasses the elegant cancellation of odd functions in the symmetric interval [−1,1][-1, 1], leading to severe algebraic entanglement and a high probability of calculation errors.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterIntegrals - Class 12
ConceptIntegral as the Limit of a Sum
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree