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Question #41445

Difficulty: 8/10 | 🟢 Free

The Question

Let In=∫−13(xn+nxn−1)exsgn(x−1) dxI_n = \int_{-1}^{3} (x^n + n x^{n-1}) e^x \text{sgn}(x-1) \, dx for n∈Nn \in \mathbb{N}, where sgn(⋅)\text{sgn}(\cdot) denotes the signum function. Find the value of ∑n=15In−(−1)ne−13n\sum_{n=1}^{5} \frac{I_n - (-1)^n e^{-1}}{3^n}.

Options

  • A.

    5e35e^3

  • B.

    5e3−e+e2435e^3 - e + \frac{e}{243}

  • C.

    5e3−2e+2e2435e^3 - 2e + \frac{2e}{243}

  • D.

    5e3−e−e2435e^3 - e - \frac{e}{243}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Monster

Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.

Concepts Behind This Question

Reduction Formulae|Method of Differences|Signum Function Discontinuity

Why This Question Is Tricky

Common Mistakes

This question tests the application of integration by parts and reduction formulae across jump discontinuities.

A common trap is to blindly apply ∫u dv=uv−∫v du\int u \, dv = uv - \int v \, du while ignoring the Dirac delta contribution from the derivative of the signum function.

This leads to the incorrect assumption that In=fn(3)+fn(−1)I_n = f_n(3) + f_n(-1), missing the −2fn(1)-2f_n(1) term generated at the boundary x=1x=1, which perfectly cascades into the trap answer 5e35e^3.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterIntegrals - Class 12
ConceptReduction Formulae
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree