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Question #41419

Difficulty: 8/10 | 🟢 Free

The Question

Evaluate the integral I=∫03π1+2sin⁡x−cos⁡x5+3cos⁡x dxI = \int_0^{3\pi} \frac{1 + 2\sin x - \cos x}{5 + 3\cos x} \, dx

Options

  • A.

    π+43ln⁡2\pi + \frac{4}{3}\ln 2

  • B.

    π3+43ln⁡2\frac{\pi}{3} + \frac{4}{3}\ln 2

  • C.

    2π3\frac{2\pi}{3}

  • D.

    π−43ln⁡2\pi - \frac{4}{3}\ln 2

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Specialist

Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.

Concepts Behind This Question

Partial Fractions Decomposition|Tangent Half-Angle Substitution|Indeterminate Forms|The Quadrant Adjustment Logic

Why This Question Is Tricky

Common Mistakes

This question tests the application of the Tangent Half-Angle (Weierstrass) substitution combined with partial fraction decomposition.

The lethal trap lies in the 'Quadrant Adjustment Logic' due to the jump discontinuity of t=tan⁡(x/2)t = \tan(x/2) at x=πx = \pi.

Students who blindly evaluate the antiderivative from the boundary conditions t(0)=0t(0)=0 to t(3π)=∞t(3\pi)=\infty without splitting the integral at the asymptote will completely miss the 2π3\frac{2\pi}{3} contribution from the second interval, leading them directly to the trap option.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterIntegrals - Class 12
ConceptPartial Fractions Decomposition
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree