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Question #41404

Difficulty: 8/10 | 🟢 Free

The Question

Let SS be the set of all twice continuously differentiable functions f:R→Rf: \mathbb{R} \to \mathbb{R} satisfying f(0)=3f(0) = 3 and ∫0x∣f(t)sin⁡tf′′(t)−sin⁡t∣dt=f(x)cos⁡x−3−sin⁡x(f′(x))3\int_0^x \begin{vmatrix} f(t) & \sin t \\ f''(t) & -\sin t \end{vmatrix} dt = f(x) \cos x - 3 - \sin x (f'(x))^3 for all x∈Rx \in \mathbb{R}. Find the value of ∑f∈Sf(π2)\sum_{f \in S} f\left(\frac{\pi}{2}\right).

Options

  • A.

    6

  • B.

    9

  • C.

    12

  • D.

    3

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Specialist

Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.

Concepts Behind This Question

Linearity and Partitioning|Differentiation of Determinants|The Zero-Factor Cancellation Trap

Why This Question Is Tricky

Common Mistakes

This question tests the differentiation of determinants and the 'Zero-Factor Cancellation Trap'.

Students must recognize that the integrand is the derivative of a determinant, applying the linearity property of determinant differentiation.

The critical trap occurs when simplifying the resulting differential equation to sin⁡x[(f′(x))3−f′(x)]=0\sin x [ (f'(x))^3 - f'(x) ] = 0.

A common mistake is to divide by f′(x)f'(x) (assuming it is non-zero), which incorrectly eliminates the constant function solution f(x)=3f(x)=3.

Furthermore, students must use the continuity of f′f' (implied by twice differentiability) to deduce that f′f' must be a constant function across the entire domain, preventing piecewise combinations.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterIntegrals - Class 12
ConceptLinearity and Partitioning
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree