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Question #41352

Difficulty: 8/10 | 🟢 Free

The Question

Let f(x)=∫0x(4t+5sgn(t−1)) dtf(x) = \int_{0}^{x} (4t + 5\text{sgn}(t-1)) \, dt, where sgn(⋅)\text{sgn}(\cdot) denotes the signum function. Let m1m_1 and m2m_2 be the left-hand and right-hand derivatives of f(x)f(x) at x=1x=1 respectively. Let L1L_1 and L2L_2 be the lines passing through the point (1,f(1))(1, f(1)) with slopes −1m1-\frac{1}{m_1} and −1m2-\frac{1}{m_2} respectively. If x1x_1 and x2x_2 are the x-intercepts of L1L_1 and L2L_2, find the value of x1x2x_1 x_2.

Options

  • A.

    -104

  • B.

    121

  • C.

    16

  • D.

    -26

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Monster

Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.

Concepts Behind This Question

Tangent/Normal Slope Interplay|Newton-Leibniz Formula with variable limits|Differentiability vs Continuity

Why This Question Is Tricky

Common Mistakes

This question tests the interplay between the Newton-Leibniz formula and the differentiability of functions defined by integrals.

The core trap lies in blindly applying the Leibniz rule to find the derivative at x=1x=1.

Since sgn(0)=0\text{sgn}(0) = 0, a student might incorrectly calculate f′(1)=4(1)+5(0)=4f'(1) = 4(1) + 5(0) = 4, leading to a single erroneous normal line with an x-intercept of −11-11, yielding an incorrect product of 121121.

The problem forces the student to recognize that the integrand is discontinuous at t=1t=1, meaning f(x)f(x) has a sharp corner (kink) at x=1x=1.

Consequently, one must evaluate the left-hand and right-hand derivatives separately by analyzing the piecewise nature of the signum function before and after the limit point.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterApplication of Derivatives - Class 12
ConceptTangent/Normal Slope Interplay
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree