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Question #41351

Difficulty: 8/10 | 🟢 Free

The Question

Let f:[1,∞)→Rf: [1, \infty) \to \mathbb{R} be a differentiable function satisfying the differential equation xdydx−y=x2−y2x \frac{dy}{dx} - y = \sqrt{x^2 - y^2} with the initial condition f(1)=0f(1) = 0. The value of f(eπ)f(e^\pi) is

Options

  • A.

    eπe^\pi

  • B.

    00

  • C.

    −eπ-e^\pi

  • D.

    eπ/2e^{\pi/2}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Specialist

Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.

Concepts Behind This Question

Tangent/Normal Slope Interplay|Homogeneous Function Homogeneity|Cross Multiplication Trap

Why This Question Is Tricky

Common Mistakes

This question tests the 'Cross Multiplication Trap' in homogeneous differential equations.

Students typically cross-multiply to get dv/1−v2=dx/xdv/\sqrt{1-v^2} = dx/x and blindly integrate to find y=xsin⁡(ln⁡x)y = x \sin(\ln x), leading to the incorrect answer f(eπ)=0f(e^\pi) = 0.

They fail to check the critical point v=1v=1 (or y=xy=x) where the denominator vanishes, which is a singular solution.

Furthermore, they ignore the non-negative range of the square root function (xv′=1−v2≥0x v' = \sqrt{1-v^2} \ge 0), which dictates that v(x)v(x) must be monotonically non-decreasing.

The true solution merges with the singular solution y=xy=x at x=eπ/2x=e^{\pi/2} and remains there, testing the student's ability to analyze the continuity and domain constraints of the tangent family.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterApplication of Derivatives - Class 12
ConceptTangent/Normal Slope Interplay
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree