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Question #41345

Difficulty: 8/10 | 🟢 Free

The Question

Let f:R→Rf: \mathbb{R} \to \mathbb{R} be a function defined by f(x)=∫x2xtsin⁡−1(sin⁡t) dtf(x) = \int_{x}^{2x} t \sin^{-1}(\sin t) \, dt Find the value of f′′(5π6)f''\left(\frac{5\pi}{6}\right).

Options

  • A.

    6π6\pi

  • B.

    35π3\frac{35\pi}{3}

  • C.

    −26π3-\frac{26\pi}{3}

  • D.

    10π3\frac{10\pi}{3}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

Rate of Change Dependency|Newton-Leibniz Formula with variable limits|Composition Inverse Identity Traps

Why This Question Is Tricky

Common Mistakes

This question tests the application of the Newton-Leibniz formula combined with the piecewise nature of composite inverse trigonometric functions.

The primary trap is the assumption that sin⁡−1(sin⁡t)=t\sin^{-1}(\sin t) = t globally, which leads to incorrect derivatives (Option B).

Students must identify the correct principal value branches for both xx and 2x2x in the neighborhood of the evaluation point before differentiating a second time.

Forgetting the chain rule multiplier in the Leibniz rule is another common pitfall (Option D).

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterApplication of Derivatives - Class 12
ConceptRate of Change Dependency
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree