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Question #41337

Difficulty: 8/10 | 🟢 Free

The Question

Let A(x)=(2{x}[x]2−4[x]+3[x]2−8[x]+15−2{x})A(x) = \begin{pmatrix} 2\{x\} & [x]^2 - 4[x] + 3 \\ [x]^2 - 8[x] + 15 & -2\{x\} \end{pmatrix}, where [x][x] denotes the greatest integer less than or equal to xx, and {x}\{x\} denotes the fractional part of xx. Let SS be the set of all x∈[0,10]x \in [0, 10] such that A(x)A(x) is a nilpotent matrix. Find the sum of all elements in SS.

Options

  • A.

    15+315 + \sqrt{3}

  • B.

    15+2315 + 2\sqrt{3}

  • C.

    99

  • D.

    1515

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Specialist

Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.

Concepts Behind This Question

Step Function Discontinuities|Nilpotent Matrix Logic|Idempotent and Involutory Properties

Why This Question Is Tricky

Common Mistakes

This question tests the intersection of matrix nilpotency and piecewise function analysis.

A common trap is assuming that det⁡(A)=0\det(A) = 0 requires the polynomial in [x][x] to be exactly zero, leading students to only find the integer roots x∈{1,3,5}x \in \{1, 3, 5\}.

By introducing the 2{x}2\{x\} terms, the determinant equation becomes a bounded Diophantine-style equation 4{x}2=−P([x])4\{x\}^2 = -P([x]).

Students must recognize that the fractional part can compensate for specific non-zero integer values of the polynomial, revealing hidden non-integer solutions.

This effectively filters out candidates who lack rigorous bounding techniques.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterContinuity and Differentiability - Class 12
ConceptStep Function Discontinuities
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree