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Question #41311

Difficulty: 8/10 | 🟢 Free

The Question

Let y=f(x)y = f(x) be the unique real-valued continuous function satisfying the implicit equation y3+y2sin⁡(∣x∣)+y=x2+2y^3 + y^2 \sin(|x|) + y = x^2 + 2 for all x∈Rx \in \mathbb{R}. If L=lim⁡x→0+f′(x)L = \lim_{x \to 0^+} f'(x) and R=lim⁡x→0−f′(x)R = \lim_{x \to 0^-} f'(x), then the value of 16∣L⋅R∣+8∣L−R∣16|L \cdot R| + 8|L - R| is

Options

  • A.

    1

  • B.

    3

  • C.

    5

  • D.

    7

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

Differentiability vs Continuity|Implicit Differentiation Rate|The Modulus Trap

Why This Question Is Tricky

Common Mistakes

This question tests the 'Modulus Trap' within implicit differentiation.

Students frequently differentiate terms like sin⁡(∣x∣)\sin(|x|) incorrectly as cos⁡(∣x∣)\cos(|x|), ignoring the chain rule for ∣x∣|x| which introduces a sgn(x)\text{sgn}(x) multiplier.

This error leads to the false conclusion that L=R=−1/4L = R = -1/4.

By evaluating the right-hand and left-hand limits separately, the problem highlights how the modulus transition at x=0x=0 causes a jump discontinuity in the derivative, rendering the continuous function non-differentiable at that point.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterContinuity and Differentiability - Class 12
ConceptDifferentiability vs Continuity
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree