Before You Begin
Question #41311
The Question
Let be the unique real-valued continuous function satisfying the implicit equation for all . If and , then the value of is
Options
- A.
1
- B.
3
- C.
5
- D.
7
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Bridge
Practice problems that bridge the gap between foundational theory and advanced practical application.
Concepts Behind This Question
Differentiability vs Continuity|Implicit Differentiation Rate|The Modulus Trap
Why This Question Is Tricky
Common Mistakes
This question tests the 'Modulus Trap' within implicit differentiation.
Students frequently differentiate terms like incorrectly as , ignoring the chain rule for which introduces a multiplier.
This error leads to the false conclusion that .
By evaluating the right-hand and left-hand limits separately, the problem highlights how the modulus transition at causes a jump discontinuity in the derivative, rendering the continuous function non-differentiable at that point.
Quick Facts About This Question
Question Information
| Subject | Mathematics |
| Chapter | Continuity and Differentiability - Class 12 |
| Concept | Differentiability vs Continuity |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |