Start Learning Free

Before You Begin

Question #41285

Difficulty: 8/10 | 🟢 Free

The Question

Let A=[aij]A = [a_{ij}] be a 4×44 \times 4 matrix where its entries are given by the binomial sum: aij=110∑k=02(−1)k(2k)(i−j+1−k)5a_{ij} = \frac{1}{10} \sum_{k=0}^2 (-1)^k \binom{2}{k} (i-j+1-k)^5 for 1≤i,j≤41 \le i, j \le 4. Let matrix BB be obtained from AA by applying the following sequence of elementary operations in order: R1↔R3R_1 \leftrightarrow R_3, C2↔C4C_2 \leftrightarrow C_4, and R2↔R4R_2 \leftrightarrow R_4. Find the value of [∣B∣1000]\left[ \frac{|B|}{1000} \right], where [⋅][ \cdot ] denotes the greatest integer function.

Options

  • A.

    -21

  • B.

    -20

  • C.

    20

  • D.

    21

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Monster

Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.

Concepts Behind This Question

Skew-Symmetric Determinant|Properties of Binomial Coefficients|Integral Part and Fractional Part|Row/Column Exchange Parity

Why This Question Is Tricky

Common Mistakes

This question tests the evaluation of finite differences disguised as binomial sums to reveal a skew-symmetric matrix.

The core JEE Advanced trap lies in the sequence of elementary operations and the greatest integer function.

Students often correctly compute the determinant of the even-order skew-symmetric matrix as a perfect square (20736).

However, they frequently miss the parity shift caused by the odd number of row/column swaps (3 swaps), leading to a sign error.

Furthermore, the greatest integer function acts as a secondary trap: even if they get the negative sign, they might incorrectly evaluate the greatest integer of -20.736 as -20 instead of -21.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterDeterminants - Class 12
ConceptSkew-Symmetric Determinant
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree