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Question #41263

Difficulty: 8/10 | 🟢 Free

The Question

For any integer m≥1m \ge 1, let Am,1,Am,2,…,Am,mA_{m,1}, A_{m,2}, \dots, A_{m,m} be mm arithmetic means inserted between −1-1 and 2m+12m+1. Let Sm=∑k=1mAm,kS_m = \sum_{k=1}^m A_{m,k} and fm(r)=∑k=1mAm,krk−1f_m(r) = \sum_{k=1}^m A_{m,k} r^{k-1}. Let dmd_m be the common difference of the arithmetic progression formed by inserting mm arithmetic means between 00 and m+1m+1. Define the matrix Mn(r)=(fn(r)fn+1(r)fn+2(r)SnSn+1Sn+2dndn+1dn+2)M_n(r) = \begin{pmatrix} f_n(r) & f_{n+1}(r) & f_{n+2}(r) \\ S_n & S_{n+1} & S_{n+2} \\ d_n & d_{n+1} & d_{n+2} \end{pmatrix} If lim⁡r→1det⁡(Mn(r))1−r=399\lim_{r \to 1} \frac{\det(M_n(r))}{1-r} = 399, then the value of nn is:

Options

  • A.

    8

  • B.

    9

  • C.

    10

  • D.

    11

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Monster

Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.

Concepts Behind This Question

Singular vs. Non-Singular Threshold|Insertion of Means|Arithmetic-Geometric Progression (AGP)

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to handle the singular threshold of a matrix whose elements are defined by Arithmetic-Geometric Progressions (AGP).

The primary trap lies in attempting to evaluate the AGP sum fm(r)f_m(r) using standard summation formulas before taking the limit r→1r \to 1, which leads to a 0/00/0 indeterminate form and complex derivatives if L'Hopital's rule is applied directly to the determinant.

By recognizing that the matrix elements are generated by mean-insertion identities, students are guided to use determinant column operations (C3→C3−C2C_3 \to C_3 - C_2, C2→C2−C1C_2 \to C_2 - C_1) first.

This elegantly collapses the AGP series into single terms, factoring out (1−r)(1-r) naturally and bypassing the singularity trap entirely.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterDeterminants - Class 12
ConceptSingular vs. Non-Singular Threshold
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree