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Question #41227

Difficulty: 8/10 | 🟢 Free

The Question

Let f:[2,∞)→[−4,∞)f: [2, \infty) \to [-4, \infty) be defined by f(x)=x2−4xf(x) = x^2 - 4x. Let g:R→[−4,∞)g: \mathbb{R} \to [-4, \infty) be defined by g(x)=x2−6∣x∣+5g(x) = x^2 - 6|x| + 5. Let h(x)=f−1(g(x))h(x) = f^{-1}(g(x)). If SS is the set of all real numbers where the derivative h′(x)h'(x) does not exist, then the value of ∑x∈Sx2+∫−44h(x)dx\sum_{x \in S} x^2 + \int_{-4}^{4} h(x) dx is:

Options

  • A.

    44

  • B.

    50

  • C.

    8

  • D.

    26

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

Composition Inverse Identity Traps|Inverse Function Derivative|Geometrical Interpretation of Modulus

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to correctly apply the identity x2=∣x∣\sqrt{x^2} = |x| when composing an inverse function with a restricted domain.

A common JEE Advanced trap is assuming f−1(f(y))=yf^{-1}(f(y)) = y universally, leading students to incorrectly write (∣x∣−3)2=∣x∣−3\sqrt{(|x|-3)^2} = |x|-3.

This ignores the outer modulus, which is mathematically invalid because the range of f−1f^{-1} is restricted to [2,∞)[2, \infty), meaning h(x)h(x) must be ≥2\ge 2.

Missing this outer modulus changes the non-differentiable points (missing ±3\pm 3) and drastically alters the area under the curve, leading directly to the trap option 8.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterInverse Trigonometric Functions - Class 12
ConceptComposition Inverse Identity Traps
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree