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Question #41222

Difficulty: 8/10 | 🟢 Free

The Question

Let w,x,y,z∈Rw, x, y, z \in \mathbb{R} such that the following matrix equation holds: (wxyz)=(∫−e−1tln⁡∣t∣dt∫−22t34−t2dt∫1etln⁡tdt∫12(3t2−2t+54)dt)\begin{pmatrix} w & x \\ y & z \end{pmatrix} = \begin{pmatrix} \int_{-e}^{-1} t \ln|t| dt & \int_{-2}^{2} \frac{t^3}{\sqrt{4-t^2}} dt \\ \int_{1}^{e} t \ln t dt & \int_{1}^{2} \left( 3t^2 - 2t + \frac{5}{4} \right) dt \end{pmatrix} Find the value of w+x+y+zw + x + y + z.

Options

  • A.

    31560\frac{315}{60}

  • B.

    e2+12\frac{e^2+1}{2}

  • C.

    214−e2+12\frac{21}{4} - \frac{e^2+1}{2}

  • D.

    \text{Does not exist}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

Matrix Equality|Integration by Parts (LIATE Rule)|Logarithmic Integration Modulus|Denominator Restriction

Why This Question Is Tricky

Common Mistakes

This question tests the rigorous application of definite integrals within matrix equality.

The primary trap lies in the element ww: forgetting the modulus in ln⁡∣t∣\ln|t| for negative bounds leads to complex numbers (e.g., ln⁡(−1)=iπ\ln(-1) = i\pi), which violates the real-field constraint w∈Rw \in \mathbb{R} and tempts students to choose 'Does not exist'.

A secondary trap is the denominator restriction in xx at t=±2t = \pm 2; students must recognize it as a convergent improper integral of an odd function.

Finally, the correct sum 21/421/4 is disguised as the unsimplified fraction 315/60315/60 to test confidence in the derived result.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterMatrices - Class 12
ConceptMatrix Equality
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree