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Question #41213

Difficulty: 8/10 | 🟢 Free

The Question

Let S={z∈C:∣z∣≤3}S = \{ z \in \mathbb{C} : |z| \le 3 \}. For any z∈Sz \in S, a matrix AA is defined as: A=([∣z∣]−111[∣z−3∣]−1−11[∣z−4i∣])A = \begin{pmatrix} [|z|] & -1 & 1 \\ 1 & [|z-3|] & -1 \\ -1 & 1 & [|z-4i|] \end{pmatrix} where [x][x] denotes the greatest integer less than or equal to xx. Let VV be the volume of the parallelepiped whose coterminous edges are the column vectors of the matrix Adj(A)\text{Adj}(A). Find the maximum possible value of VV.

Options

  • A.

    10816

  • B.

    15129

  • C.

    9604

  • D.

    104

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Monster

Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.

Concepts Behind This Question

Adjoint-Determinant Relation|Scalar Triple Product Volume Logic|Geometrical Interpretation of Modulus|Greatest Integer Function Traps

Why This Question Is Tricky

Common Mistakes

This question tests the synthesis of matrix adjoint properties (∣Adj(A)∣=∣A∣n−1|\text{Adj}(A)| = |A|^{n-1}) with complex number geometry and the Greatest Integer Function (GIF).

The primary trap lies in the 'independent maximization fallacy': students often find the maximum possible values of [∣z−3∣][|z-3|] and [∣z−4i∣][|z-4i|] independently (66 and 77) and incorrectly assume they can occur simultaneously, leading to a determinant of 123123 and a trap volume of 1512915129.

Rigorous parameterization of zz on the circle ∣z∣=3|z|=3 is required to find the true coupled maximum of the piecewise constant determinant function.

A secondary trap is forgetting the square in the volume formula, leading to option D.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterMatrices - Class 12
ConceptAdjoint-Determinant Relation
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree