Before You Begin
Question #41199
The Question
Let for . Define the function by the infinite series: Let . Find the value of .
Options
- A.
-64
- B.
64
- C.
-48
- D.
48
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Monster
Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.
Concepts Behind This Question
Infinite Series involving Inverse Tangent|De Moivre’s Theorem Applications|Chain Rule Complexity|Implicit to Explicit Conversion
Why This Question Is Tricky
Common Mistakes
This question tests the student's ability to correctly transition from an implicit algebraic complex number to its explicit trigonometric form using De Moivre's Theorem, while rigorously handling the principal argument and branch cuts.
The core trap lies in the evaluation of the infinite sine series (derived via the Taylor series of the complex logarithm).
Students frequently memorize the standard Fourier series result without the domain restriction .
For negative , the argument falls in .
Because the modulus of the complex logarithm must be positive, a phase shift of occurs, requiring the odd extension of the series which yields .
Failing to account for this branch cut leads to a sign error in the explicit function , resulting in the trap answer instead of after applying the Chain Rule.
Quick Facts About This Question
Question Information
| Subject | Mathematics |
| Chapter | Inverse Trigonometric Functions - Class 12 |
| Concept | Infinite Series involving Inverse Tangent |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |