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Question #41191

Difficulty: 8/10 | 🟢 Free

The Question

Let SS be the set of all complex numbers z=x+iyz = x + iy where x,y∈Zx, y \in \mathbb{Z}, satisfying the following two conditions:

(i) tan⁡−1(x)+tan⁡−1(y)=tan⁡−1(x+y1−xy)\tan^{-1}(x) + \tan^{-1}(y) = \tan^{-1}\left(\frac{x+y}{1-xy}\right)

(ii) cos⁡−1(x2+y2−55)⋅(x2+y2−8)≤0\cos^{-1}\left(\frac{x^2+y^2 - 5}{5}\right) \cdot (x^2+y^2 - 8) \le 0

Find the number of elements in SS.

Options

  • A.

    17

  • B.

    21

  • C.

    25

  • D.

    33

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

The Sum-Difference Formula Constraints|Locus Problems via Transformation|The Zero-Factor Cancellation Trap|Wavy Curve (Method of Intervals)

Why This Question Is Tricky

Common Mistakes

This question tests the student's rigor in handling inverse trigonometric identities and inequalities.

The primary trap is a 'Zero-Factor Cancellation' hazard.

In Condition (ii), students often divide by cos⁡−1(x2+y2−55)\cos^{-1}\left(\frac{x^2+y^2-5}{5}\right) assuming it is strictly positive, thereby solving only x2+y2≤8x^2+y^2 \le 8 and losing the discrete solution set x2+y2=10x^2+y^2 = 10 where the inverse cosine evaluates to zero.

Additionally, Condition (i) requires knowledge of the sum formula constraint xy<1xy < 1, which restricts the locus to specific quadrants.

Failing to account for the zero-factor hides valid points in the Wavy Curve solution, leading to the trap answer 17.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterInverse Trigonometric Functions - Class 12
ConceptThe Sum-Difference Formula Constraints
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree