Start Learning Free

Before You Begin

Question #41173

Difficulty: 8/10 | 🟢 Free

The Question

A curve CC in R3\mathbb{R}^3 is defined by the intersection of the surfaces x3+3x=4yx^3 + 3x = 4y and y3+y=2zy^3 + y = 2z. Let LL be the tangent line to the curve CC at the point P(1,1,1)P(1, 1, 1). If θ\theta is the acute angle between the line LL and the plane 6x−2y+3z=106x - 2y + 3z = 10, find the value of 49sin⁡θ49 \sin \theta.

Options

  • A.

    15

  • B.

    18

  • C.

    24

  • D.

    36

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

Derivative of Implicit Inverse Forms|Angle between line and plane|Parametric form pitfalls

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to correctly extract the direction vector of a 3D curve defined by implicit inverse forms.

The primary trap lies in the 'Parametric form pitfall.' Students often incorrectly assume the direction vector is simply ⟨dxdy,dydz,1⟩\langle \frac{dx}{dy}, \frac{dy}{dz}, 1 \rangle or ⟨1,dydx,dzdy⟩\langle 1, \frac{dy}{dx}, \frac{dz}{dy} \rangle without applying the chain rule properly across the parameters, leading to erroneous vectors like ⟨4,3,6⟩\langle 4, 3, 6 \rangle (which yields the trap answer 36) or ⟨2,3,4⟩\langle 2, 3, 4 \rangle (yielding 18).

Furthermore, students might confuse the gradients of the implicit surfaces with the direction vector of the curve itself.

Proper parametrization or the cross-product of gradients is required to preserve the orientation parameter.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterInverse Trigonometric Functions - Class 12
ConceptDerivative of Implicit Inverse Forms
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree