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Question #41157
The Question
Let and . Define the function as the determinant Let be the set of all such that . Then the value of is equal to:
Options
- A.
- B.
- C.
- D.
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Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Monster
Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.
Concepts Behind This Question
Principal Value Branch Boundaries|Differentiation of Determinants|Singular vs. Non-Singular Threshold
Why This Question Is Tricky
Common Mistakes
This question tests the student's mastery of the principal value branches of inverse trigonometric functions and their piecewise derivatives.
A common trap is mechanically assuming and globally, which leads to the false conclusion that the determinant has no roots in the given interval.
By forcing the student to find the singular points of the matrix, they must correctly apply the piecewise definitions or and .
Furthermore, evaluating the derivative of the determinant requires recognizing that the derivatives of these composite functions are step functions () depending on the quadrant, penalizing students who blindly differentiate without checking the domain validity at the specific roots.
Quick Facts About This Question
Question Information
| Subject | Mathematics |
| Chapter | Inverse Trigonometric Functions - Class 12 |
| Concept | Principal Value Branch Boundaries |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |