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Question #41134

Difficulty: 8/10 | 🟢 Free

The Question

Let f:(−π2,π2)→Rf: \left(-\frac{\pi}{2}, \frac{\pi}{2}\right) \to \mathbb{R} be defined by f(x)={x2sin⁡x+x2sin⁡(1x)if x≠00if x=0f(x) = \begin{cases} \frac{x^2}{\sin x} + x^2 \sin\left(\frac{1}{x}\right) & \text{if } x \neq 0 \\ 0 & \text{if } x = 0 \end{cases} Let g(x)=2π−xg(x) = \frac{2}{\pi} - x. Consider the composite functions H1(x)=f(g(x))H_1(x) = f(g(x)) and H2(x)=g(f(x))H_2(x) = g(f(x)). Which of the following statements is TRUE regarding the existence of local inverses for H1H_1 and H2H_2 in some neighborhood (−δ,δ)(-\delta, \delta) of x=0x = 0 (where δ>0\delta > 0 is sufficiently small)?

Options

  • A.

    H1H_1 is invertible on (−δ,δ)(-\delta, \delta), but H2H_2 is not.

  • B.

    H2H_2 is invertible on (−δ,δ)(-\delta, \delta), but H1H_1 is not.

  • C.

    Both H1H_1 and H2H_2 are invertible on (−δ,δ)(-\delta, \delta).

  • D.

    Neither H1H_1 nor H2H_2 is invertible on (−δ,δ)(-\delta, \delta).

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Specialist

Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.

Concepts Behind This Question

Composition Non-Commutativity|Inverse Existence Criterion|The L'Hôpital's Rule Misuse

Why This Question Is Tricky

Common Mistakes

This question tests the misconception that a positive derivative at a single point (f′(0)>0f'(0) > 0) guarantees local monotonicity and invertibility.

Students are baited into using L'Hôpital's rule to evaluate f′(0)f'(0) via the limit of the derivative, which leads to a non-existent limit, causing them to falsely conclude ff is non-differentiable.

If they correctly find f′(0)=1f'(0)=1, they often incorrectly assume f(x)f(x) is invertible near 00.

Furthermore, the non-commutativity of composition is exploited: H2(x)H_2(x) evaluates ff near the pathological point x=0x=0, inheriting its non-monotonicity, whereas H1(x)H_1(x) evaluates ff near x=2/πx=2/\pi, where ff is smooth and strictly monotonic, making H1H_1 invertible.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterRelations and Functions - Class 12
ConceptComposition Non-Commutativity
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree