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Question #41091

Difficulty: 8/10 | 🟢 Free

The Question

Let XX be a discrete random variable taking values in the set {0,1,2,…,5055}\{0, 1, 2, \dots, 5055\}. The probability mass function of XX is given by P(X=r)=ar61011P(X = r) = \frac{a_r}{6^{1011}}, where ara_r is the coefficient of xrx^r in the expansion of (1+x+x2+x3+x4+x5)1011(1 + x + x^2 + x^3 + x^4 + x^5)^{1011}. Let F(x)=P(X≤x)F(x) = P(X \le x) be the cumulative distribution function of XX. Find the value of ∑r=050552[2F(r)]\sum_{r=0}^{5055} 2^{[2 F(r)]} where [⋅][ \cdot ] denotes the greatest integer function.

Options

  • A.

    7584

  • B.

    7585

  • C.

    7586

  • D.

    7587

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

Random Variable Mapping|Coefficient of x^r in Expansion|Step Function Discontinuities

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to analyze the cumulative distribution function (CDF) of a symmetric multinomial expansion under the transformation of a step function.

The primary trap lies in the boundary conditions and the exact median of the distribution.

Students often correctly identify the symmetry F(r)+F(M−1−r)=1F(r) + F(M-1-r) = 1 but incorrectly assume [2F(r)][2F(r)] splits symmetrically.

They fail to account for the fact that F(r)F(r) equals exactly 1/21/2 at the median r=2527r=2527, causing an asymmetric jump in the greatest integer function.

Furthermore, missing the exact value F(5055)=1F(5055)=1 leads to an incorrect evaluation of the final term.

These discontinuities force off-by-one errors, perfectly mapping to the incorrect options provided.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterProbability - Class 11
ConceptRandom Variable Mapping
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree