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Question #41083
The Question
Let be a function defined on the sample space . A continuous random variable takes values in with a probability density function . Let and be the points in where attains its global minimum and global maximum, respectively. Let be the event that , and be the event that falls in the interval where the graph of is strictly concave downward. Calculate the probability .
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Monster
Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.
Concepts Behind This Question
De Morgan’s Laws in Probability|Global Extrema on Intervals|Second Derivative Test Limitations
Why This Question Is Tricky
Common Mistakes
The question tests the student's ability to synthesize global extrema analysis, concavity, and De Morgan's laws within a continuous probability framework.
The primary trap lies in the evaluation of the global maximum.
Students often rely exclusively on the Second Derivative Test to classify extrema.
For , , making the test inconclusive.
A common failure mode is incorrectly assuming is a local/global maximum without checking the boundaries of .
If a student neglects the boundary (where the true global maximum occurs) and assumes the maximum is at , they incorrectly define Event as .
This leads to and a cascading error resulting in the trap answer .
Furthermore, the disjoint nature of the correct intervals requires careful application of De Morgan's law .
Quick Facts About This Question
Question Information
| Subject | Mathematics |
| Chapter | Probability - Class 11 |
| Concept | De Morgan’s Laws in Probability |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |