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Question #41070

Difficulty: 8/10 | 🟢 Free

The Question

Let S={−2,−1,0,1,2}S = \{-2, -1, 0, 1, 2\}. A 2×22 \times 2 matrix AA is formed by choosing its entries randomly with replacement from SS. What is the probability that A3≠OA^3 \neq O, where OO is the 2×22 \times 2 null matrix?

Options

  • A.

    608625\frac{608}{625}

  • B.

    616625\frac{616}{625}

  • C.

    624625\frac{624}{625}

  • D.

    598625\frac{598}{625}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

Complementary Counting|Sample Space Partitioning|Nilpotent Matrix Logic

Why This Question Is Tricky

Common Mistakes

This question tests the student's understanding of nilpotent matrices and complementary counting.

The primary trap is the assumption that A3=O  ⟹  A=OA^3 = O \implies A = O, leading to the incorrect probability of 624/625624/625.

Furthermore, students often fail to realize that for a 2×22 \times 2 matrix, the index of nilpotency cannot exceed 2, meaning A3=O  ⟺  A2=OA^3 = O \iff A^2 = O.

By partitioning the sample space based on the trace and determinant conditions (Tr(A)=0,det⁡(A)=0\text{Tr}(A)=0, \det(A)=0), and using complementary counting, we avoid the tedious direct calculation of A3≠OA^3 \neq O and prevent double-counting errors in the matrix space distribution.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterProbability - Class 11
ConceptComplementary Counting
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree