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Question #41010

Difficulty: 8/10 | 🟢 Free

The Question

Let AA and BB be two events associated with a random experiment. The probability of event AA is given by P(A)=det⁡(M)P(A) = \det(M), where MM is the 3×33 \times 3 matrix: M=(∫−π/4π/4ln⁡(1−sin⁡x1+sin⁡x)dxα2+1β−(α2+1)∑k=159(cos⁡kπ2−cos⁡−kπ2)γ−β−γlim⁡x→0ex2−1−x2x4−12)M = \begin{pmatrix} \int_{-\pi/4}^{\pi/4} \ln\left(\frac{1-\sin x}{1+\sin x}\right) dx & \alpha^2+1 & \beta \\ -(\alpha^2+1) & \sum_{k=1}^{59} \left( \cos\frac{k\pi}{2} - \cos\frac{-k\pi}{2} \right) & \gamma \\ -\beta & -\gamma & \lim_{x \to 0} \frac{e^{x^2} - 1 - x^2}{x^4} - \frac{1}{2} \end{pmatrix} for some real constants α,β,γ\alpha, \beta, \gamma. Event BB is defined as the event that a number tt chosen at random from the sample space S={t∈Z:−59≤t≤283}S = \{t \in \mathbb{Z} : -59 \le t \le 283\} satisfies the inequality: (t−59)2(t−283)<0(t-59)^2 (t-283) < 0 Find the value of 343×P(Ac∩B)343 \times P(A^c \cap B).

Options

  • A.

    340

  • B.

    341

  • C.

    342

  • D.

    343

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Monster

Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.

Concepts Behind This Question

Algebra of Events|Skew-Symmetric Determinant|Even Multiplicity Roots|Even and Odd Function Symmetry

Why This Question Is Tricky

Common Mistakes

The question tests two major traps in a combined algebraic and probabilistic setting.

First, it masks the probability of event A as the determinant of a matrix.

Students must recognize that the diagonal elements evaluate to zero due to odd function symmetry, even function properties, and standard limits, making MM a 3×33 \times 3 skew-symmetric matrix whose determinant is identically zero.

Thus, P(A)=0P(A) = 0, which simplifies P(Ac∩B)P(A^c \cap B) to just P(B)P(B).

Second, in calculating P(B)P(B), the inequality (t−59)2(t−283)<0(t-59)^2(t-283) < 0 contains an even multiplicity root at t=59t=59.

A common mistake is to only solve t<283t < 283 and count 342 integers, forgetting that the strict inequality fails at t=59t=59.

Excluding this root collapses the valid event space size to 341, forcing a precise re-evaluation of the set.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterProbability - Class 11
ConceptAlgebra of Events
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree