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Question #41005

Difficulty: 8/10 | 🟢 Free

The Question

Let XX be a continuous random variable with probability density function f(x)=k(x2+∣x∣)f(x) = k(x^2 + |x|) for x∈[−3,3]x \in [-3, 3] and f(x)=0f(x) = 0 otherwise. Let EE be the event that the random variable XX satisfies the inequality: ∫−XX(t3cos⁡t+t2sin⁡3t+∣t∣−1)dt>0\int_{-X}^{X} \left( t^3 \cos t + t^2 \sin^3 t + |t| - 1 \right) dt > 0 Find the probability of event EE, P(E)P(E).

Options

  • A.

    12\frac{1}{2}

  • B.

    6781\frac{67}{81}

  • C.

    5381\frac{53}{81}

  • D.

    1936\frac{19}{36}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

Sample Space Construction|Sample Space Partitioning|Symmetry Utilization|Even and Odd Function Symmetry

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to construct and partition a sample space using the properties of definite integrals, specifically even and odd function symmetry.

The primary trap lies in evaluating the integral with variable limits [−X,X][-X, X].

Students often incorrectly assume the integral evaluates to X2−2XX^2 - 2X or ∣X∣2−2∣X∣|X|^2 - 2|X| for all XX, ignoring the sign change introduced by the upper and lower limits when X<0X < 0.

This failure to utilize parity correctly leads to an improper partitioning of the sample space (e.g., yielding X∈[−3,0)∪(2,3]X \in [-3, 0) \cup (2, 3]), which cascades into incorrect integration limits for the probability density function and results in the common distractor 67/81.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterProbability - Class 11
ConceptSample Space Construction
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree