Start Learning Free

Before You Begin

Question #40980

Difficulty: 8/10 | 🟢 Free

The Question

Let z1,z2,z3,z4z_1, z_2, z_3, z_4 be the roots of the polynomial equation z4−αz3+βz2−γz+1=0z^4 - \alpha z^3 + \beta z^2 - \gamma z + 1 = 0, where α,β,γ∈C\alpha, \beta, \gamma \in \mathbb{C}. Given that ∣α∣=4|\alpha| = 4, the arithmetic mean of the moduli of the roots is 11, and Im(α)>0\text{Im}(\alpha) > 0. The value of ∣β+γ∣2|\beta + \gamma|^2 is:

Options

  • A.

    52

  • B.

    100

  • C.

    20

  • D.

    68

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

Properties of Arithmetic Mean|Vieta’s Formulas in Complex Domain|Geometrical Interpretation of Modulus

Why This Question Is Tricky

Common Mistakes

The core trap in this problem lies in the Geometrical Interpretation of Modulus, specifically the equality condition of the triangle inequality in the complex plane.

Students often attempt to use Vieta's formulas to find the sum of the roots (∣∑zk∣=4|\sum z_k| = 4) and then incorrectly treat the complex roots as independent scalars when relating them to the sum of their moduli (∑∣zk∣=4\sum |z_k| = 4).

The 'Lethal Collision' occurs if they fail to recognize that ∣∑zk∣=∑∣zk∣|\sum z_k| = \sum |z_k| strictly forces all roots to lie on the same ray from the origin (zk=rkeiθz_k = r_k e^{i\theta}).

Bypassing this geometric deduction prevents the subsequent application of the AM-GM inequality (AM=GM=1\text{AM} = \text{GM} = 1) required to prove that all roots are identical, leaving the polynomial unsolvable.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterStatistics - Class 11
ConceptProperties of Arithmetic Mean
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree