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Question #40935

Difficulty: 8/10 | 🟢 Free

The Question

Evaluate the following limit: lim⁡x→0(1x2∫0x21+2t21+t2 dt)csc⁡4x\lim_{x \to 0} \left( \frac{1}{x^2} \int_0^{x^2} \frac{1+2t^2}{\sqrt{1+t^2}} \, dt \right)^{\csc^4 x}

Options

  • A.

    e\sqrt{e}

  • B.

    ee

  • C.

    e1/3e^{1/3}

  • D.

    11

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Specialist

Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.

Concepts Behind This Question

The 1^∞ Form Shortcut|Integrating f(x) + xf'(x) forms|Fundamental Theorem of Calculus

Why This Question Is Tricky

Common Mistakes

This question tests the synergy between the 1∞1^\infty limit form and the Fundamental Theorem of Calculus (Leibniz Rule).

The primary trap lies in the evaluation of the base limit.

Students who blindly apply L'Hopital's rule to the 1∞1^\infty exponent expression ∫0x2...dt−x2x2sin⁡4x\frac{\int_0^{x^2} ... dt - x^2}{x^2 \sin^4 x} often fall victim to the chain rule trap in FTC, forgetting to multiply by the derivative of the upper limit (2x2x).

Alternatively, recognizing the integrand as the exact derivative of tf(t)t f(t) bypasses the complex differentiation entirely, rewarding algebraic foresight over brute-force calculus.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterLimits and Derivatives - Class 11
ConceptThe 1^∞ Form Shortcut
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree