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Question #40934

Difficulty: 8/10 | 🟢 Free

The Question

Let AA be a 3×33 \times 3 real skew-symmetric matrix such that Tr(AAT)=28\text{Tr}(A A^T) = 28. Let M(x)=I+sin⁡(x)A+tan⁡2(x)ATAM(x) = I + \sin(x) A + \tan^2(x) A^T A, where II is the 3×33 \times 3 identity matrix. Evaluate the limit: L=lim⁡x→0(det⁡(M(x)))1x2L = \lim_{x \to 0} \left( \det(M(x)) \right)^{\frac{1}{x^2}}

Options

  • A.

    e42e^{42}

  • B.

    e28e^{28}

  • C.

    e14e^{14}

  • D.

    Does not exist

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

The 1^∞ Form Shortcut|Properties of Transpose Determinant|Matrix Equality

Why This Question Is Tricky

Common Mistakes

This question tests the 1∞1^\infty limit form combined with matrix properties, specifically targeting the 'Matrix Equality' trap.

Students often confuse the limit of a scalar determinant with the determinant of a matrix limit.

If a student attempts to evaluate the matrix limit lim⁡x→0M(x)1x2\lim_{x \to 0} M(x)^{\frac{1}{x^2}} using the matrix exponential elim⁡M(x)−Ix2e^{\lim \frac{M(x)-I}{x^2}}, they will encounter the term sin⁡xx2A\frac{\sin x}{x^2} A, which diverges.

This leads them to incorrectly conclude that the limit 'Does not exist'.

However, the determinant is a scalar function; the divergent O(1/x)O(1/x) terms in the matrix eigenvalues are complex conjugates that cancel out upon multiplication, resulting in a perfectly well-defined scalar limit.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterLimits and Derivatives - Class 11
ConceptThe 1^∞ Form Shortcut
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree