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Question #40921

Difficulty: 8/10 | 🟢 Free

The Question

Let f:[0,∞)→Rf: [0, \infty) \to \mathbb{R} be defined by f(x)=∫0x∣sin⁡t∣−sin⁡t2ecos⁡tdtf(x) = \int_0^x \frac{|\sin t| - \sin t}{2} e^{\cos t} dt Let C=e−1eC = e - \frac{1}{e}. For each integer n≥1n \ge 1, let ana_n and bnb_n be the unique positive real numbers satisfying f(an)=5C−1nandf(bn)=5C+1nf(a_n) = 5C - \frac{1}{n} \quad \text{and} \quad f(b_n) = 5C + \frac{1}{n} Find the value of lim⁡n→∞(3an−bn)\lim_{n \to \infty} (3a_n - b_n).

Options

  • A.

    19π19\pi

  • B.

    20π20\pi

  • C.

    21π21\pi

  • D.

    22π22\pi

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

Definition of Limit|Increasing/Decreasing Strictness|Monotonicity and Boundedness|Region Ambiguity

Why This Question Is Tricky

Common Mistakes

This question targets the 'Plateau Trap' in the context of limits and monotonicity.

Students often heuristically assume that a function defined by an integral with a non-negative integrand is strictly increasing globally.

However, the region ambiguity introduced by the absolute value creates intervals where the derivative is zero, resulting in plateaus.

When evaluating the limit of the inverse sequence, students who ignore the plateau will incorrectly assume both ana_n and bnb_n converge to the same point (yielding 20π20\pi or 22π22\pi), or guess the midpoint (21π21\pi).

The rigorous approach requires identifying that ana_n approaches the left endpoint of the plateau from below, while bnb_n approaches the right endpoint from above, leading to the correct asymmetric limit.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterLimits and Derivatives - Class 11
ConceptDefinition of Limit
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree