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Question #40913

Difficulty: 8/10 | 🟢 Free

The Question

Let PP be the unique point in the first quadrant that lies on both the conics C1:x2−y2−8x+4y+12=0C_1: x^2 - y^2 - 8x + 4y + 12 = 0 and C2:x2−8y=0C_2: x^2 - 8y = 0. Let AA and BB be the orthogonal projections of PP onto the xx-axis and yy-axis, respectively. A ray of light emanating from AA strikes the parabola y2=16xy^2 = 16x at a point QQ and, after reflection, travels along a straight line that passes through BB. The length of the segment AQAQ is:

Options

  • A.

    174\frac{17}{4}

  • B.

    154\frac{15}{4}

  • C.

    172\frac{17}{2}

  • D.

    5

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Specialist

Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.

Concepts Behind This Question

Coordinate Axis Projections|Intersection of Conics|Reflective Property

Why This Question Is Tricky

Common Mistakes

This question tests the intersection of degenerate conics and the geometric reflective properties of parabolas.

The primary trap lies in the reflection step: students who fail to recognize that the projection point A(4,0) is the exact focus of the parabola will attempt to use the general algebraic formula for the image of a point across a tangent line at Q(4t^2, 8t).

This brute-force method leads to a complex cubic equation (4t^3 - t^2 + 4t - 1 = 0) that is highly prone to calculation errors and consumes significant time.

Recognizing the focus geometrically forces the reflected ray to be parallel to the x-axis, bypassing the algebraic swamp entirely and rewarding geometric intuition.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterIntroduction to Three-dimensional Geometry - Class 11
ConceptCoordinate Axis Projections
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree