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Question #40905

Difficulty: 8/10 | 🟢 Free

The Question

Let a⃗=4i^+4j^−2k^\vec{a} = 4\hat{i} + 4\hat{j} - 2\hat{k} and c⃗=i^+j^+k^\vec{c} = \hat{i} + \hat{j} + \hat{k}. Let B(b⃗)B(\vec{b}) be a variable point on the sphere ∣r⃗∣=9|\vec{r}| = 9. A point P(p⃗)P(\vec{p}) lies on the line segment ABAB such that AP:PB=k:1AP:PB = k:1 (k>0k>0). For any position of BB such that a⃗,b⃗,c⃗\vec{a}, \vec{b}, \vec{c} are non-coplanar, the volume of the parallelepiped with coterminous edges kp⃗,kb⃗,kc⃗k\vec{p}, k\vec{b}, k\vec{c} is 1616 times the volume of the tetrahedron with coterminous edges a⃗,b⃗,c⃗\vec{a}, \vec{b}, \vec{c}. If the locus of PP is a sphere SS, find the maximum distance of a point on SS from the origin.

Options

  • A.

    6

  • B.

    8

  • C.

    10

  • D.

    12

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

Ratio of Division (k:1)|Scalar Triple Product Volume Logic|Determinant as Geometric Area/Volume

Why This Question Is Tricky

Common Mistakes

This problem tests the integration of 3D geometry loci with the properties of the Scalar Triple Product (STP).

The primary trap lies in the determinant scaling property: students frequently assume the volume scales linearly with the scalar multiple of the vectors, erroneously writing [kp⃗,kb⃗,kc⃗]=k[p⃗,b⃗,c⃗][k\vec{p}, k\vec{b}, k\vec{c}] = k[\vec{p}, \vec{b}, \vec{c}] instead of the correct cubic scaling k3[p⃗,b⃗,c⃗]k^3[\vec{p}, \vec{b}, \vec{c}].

Furthermore, the problem exploits the distinction between the volume of a parallelepiped (STP) and a tetrahedron (16\frac{1}{6} STP).

Failing to account for the k3k^3 factor or the 16\frac{1}{6} multiplier leads to an incorrect polynomial for kk, preventing the resolution of the locus.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterIntroduction to Three-dimensional Geometry - Class 11
ConceptRatio of Division (k:1)
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree