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Question #40903

Difficulty: 8/10 | 🟢 Free

The Question

Let P1:x+y+z=5P_1: x+y+z=5 and P2:x+y−z=5P_2: x+y-z=5 be two planes. Let Π\Pi be the plane passing through the line of intersection of P1P_1 and P2P_2, and perpendicular to the xyxy-plane. Let Π′\Pi' be the plane x+y+5=0x+y+5=0. For any point P(x,y,z)P(x,y,z) and a plane AA, let dalg(P,A)d_{alg}(P, A) denote the algebraic distance from PP to AA with respect to the unit normal vector of AA that has a positive xx-component. Let LL be the zz-axis, and d(P,L)d(P, L) be the perpendicular distance from PP to LL. A point P(x,y,z)P(x,y,z) moves in the region bounded by 0≤x≤60 \le x \le 6, 0≤y≤60 \le y \le 6, and 0≤z≤40 \le z \le 4 such that it satisfies the inequality: d(P,L)2−25dalg(P,Π)≤2dalg(P,Π′)\frac{d(P, L)^2 - 25}{d_{alg}(P, \Pi)} \le 2 d_{alg}(P, \Pi') What is the volume of the region representing the locus of PP?

Options

  • A.

    94

  • B.

    144

  • C.

    50

  • D.

    72

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

Locus via Distance Constraints|Equation of plane through intersection|Wavy Curve (Method of Intervals)

Why This Question Is Tricky

Common Mistakes

The question tests the student's ability to handle rational inequalities in coordinate geometry, specifically employing the 'Wavy Curve' trap in a 3D spatial context.

A common mistake is to cross-multiply the denominator dalg(P,Π)d_{alg}(P, \Pi) without considering its sign.

If a student blindly cross-multiplies x+y−5x+y-5, they obtain x2+y2−25≤(x+y−5)(x+y+5)x^2+y^2-25 \le (x+y-5)(x+y+5), which simplifies to −2xy≤0  ⟹  xy≥0-2xy \le 0 \implies xy \ge 0.

Since x,y≥0x, y \ge 0 in the given domain, this incorrect step implies the inequality is always true, leading to the entire 6×6×46 \times 6 \times 4 region being considered valid (Volume = 144).

By requiring the sign analysis of the denominator, the problem correctly restricts the locus to x+y>5x+y > 5, yielding the true volume of 94.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterIntroduction to Three-dimensional Geometry - Class 11
ConceptLocus via Distance Constraints
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree