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Question #40903
The Question
Let and be two planes. Let be the plane passing through the line of intersection of and , and perpendicular to the -plane. Let be the plane . For any point and a plane , let denote the algebraic distance from to with respect to the unit normal vector of that has a positive -component. Let be the -axis, and be the perpendicular distance from to . A point moves in the region bounded by , , and such that it satisfies the inequality: What is the volume of the region representing the locus of ?
Options
- A.
94
- B.
144
- C.
50
- D.
72
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Bridge
Practice problems that bridge the gap between foundational theory and advanced practical application.
Concepts Behind This Question
Locus via Distance Constraints|Equation of plane through intersection|Wavy Curve (Method of Intervals)
Why This Question Is Tricky
Common Mistakes
The question tests the student's ability to handle rational inequalities in coordinate geometry, specifically employing the 'Wavy Curve' trap in a 3D spatial context.
A common mistake is to cross-multiply the denominator without considering its sign.
If a student blindly cross-multiplies , they obtain , which simplifies to .
Since in the given domain, this incorrect step implies the inequality is always true, leading to the entire region being considered valid (Volume = 144).
By requiring the sign analysis of the denominator, the problem correctly restricts the locus to , yielding the true volume of 94.
Quick Facts About This Question
Question Information
| Subject | Mathematics |
| Chapter | Introduction to Three-dimensional Geometry - Class 11 |
| Concept | Locus via Distance Constraints |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |