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Question #40870

Difficulty: 8/10 | 🟢 Free

The Question

Let A(2,0,0)A(2, 0, 0), B(0,3,0)B(0, 3, 0), and C(0,0,6)C(0, 0, 6) be three points in R3\mathbb{R}^3. Let n⃗1=AC⃗×AB⃗\vec{n}_1 = \vec{AC} \times \vec{AB} and n^1\hat{n}_1 be the unit vector along n⃗1\vec{n}_1. Let P2P_2 be the plane 2x−y+3z=42x - y + 3z = 4 with normal vector n⃗2=2i^−j^+3k^\vec{n}_2 = 2\hat{i} - \hat{j} + 3\hat{k} and n^2\hat{n}_2 be the unit vector along n⃗2\vec{n}_2. Let Π\Pi be the plane bisecting the acute angle between the plane ABCABC and P2P_2. If n⃗3\vec{n}_3 is the normal vector to Π\Pi expressed in the form n⃗3=αn^1+βn^2\vec{n}_3 = \alpha \hat{n}_1 + \beta \hat{n}_2 where α>0\alpha > 0, find the scalar projection of the vector v⃗=5i^−j^+4k^\vec{v} = 5\hat{i} - \hat{j} + 4\hat{k} onto n⃗3\vec{n}_3.

Options

  • A.

    −204221-\frac{20\sqrt{42}}{21}

  • B.

    204221\frac{20\sqrt{42}}{21}

  • C.

    −104221-\frac{10\sqrt{42}}{21}

  • D.

    104221\frac{10\sqrt{42}}{21}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

Coordinate Axis Projections|Angle between two planes|Vector Product Anti-Commutativity

Why This Question Is Tricky

Common Mistakes

This question tests the student's attention to the anti-commutativity of the vector cross product (A⃗×B⃗=−B⃗×A⃗\vec{A} \times \vec{B} = -\vec{B} \times \vec{A}) when defining plane normals, and its cascading effect on finding the acute angle bisector.

Students often habitually compute the normal as AB⃗×AC⃗\vec{AB} \times \vec{AC} regardless of the specified order AC⃗×AB⃗\vec{AC} \times \vec{AB}.

This sign error flips the sign of the dot product n^1⋅n^2\hat{n}_1 \cdot \hat{n}_2 from negative to positive.

Consequently, they incorrectly select n^1+n^2\hat{n}_1 + \hat{n}_2 instead of n^1−n^2\hat{n}_1 - \hat{n}_2 for the acute bisector normal, leading to a sign reversal in the final scalar projection.

The trap exploits the assumption that normal vector orientation is arbitrary when bisecting planes.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterIntroduction to Three-dimensional Geometry - Class 11
ConceptCoordinate Axis Projections
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree