Start Learning Free

Before You Begin

Question #40865

Difficulty: 8/10 | 🟢 Free

The Question

Let a⃗=i^+2j^+3k^\vec{a} = \hat{i} + 2\hat{j} + 3\hat{k}, b⃗=2i^+3j^+4k^\vec{b} = 2\hat{i} + 3\hat{j} + 4\hat{k}, and c⃗=3i^+λj^+5k^\vec{c} = 3\hat{i} + \lambda\hat{j} + 5\hat{k} be three coplanar vectors. A point PP with position vector p⃗=xi^+yj^+zk^\vec{p} = x\hat{i} + y\hat{j} + z\hat{k} divides the line segment joining A(0,4,2)A(0, 4, 2) and B(2,0,4)B(2, 0, 4) internally in the ratio k:1k:1. If p⃗\vec{p} satisfies the system of equations p⃗⋅a⃗=14\vec{p} \cdot \vec{a} = 14 p⃗⋅b⃗=20\vec{p} \cdot \vec{b} = 20 p⃗⋅c⃗=μ\vec{p} \cdot \vec{c} = \mu and the system is consistent, then the value of μ\mu and the set of all possible values for kk are:

Options

  • A.

    μ=26,  k=1\mu = 26, \; k = 1

  • B.

    μ=26,  k∈(0,∞)\mu = 26, \; k \in (0, \infty)

  • C.

    μ=24,  k=2\mu = 24, \; k = 2

  • D.

    μ=24,  k∈(0,∞)\mu = 24, \; k \in (0, \infty)

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

Ratio of Division (k:1)|Collinearity vs Coplanarity|Cramer's Rule Constraints

Why This Question Is Tricky

Common Mistakes

This question tests the intersection of 3D vector geometry with systems of linear equations (Cramer's Rule).

The primary trap lies in the assumption that a system of plane equations will yield a unique point PP, and thus a unique ratio kk.

By forcing the scalar triple product to zero, the system becomes dependent (Δ=0\Delta = 0).

Students must use the consistency condition (Δx=0\Delta_x = 0) to find μ\mu.

The 'Lethal Collision' occurs when substituting the section formula coordinates into the plane equations results in an identity (14=1414=14).

Students often misinterpret this as a calculation error or assume a default value like k=1k=1, failing to realize that the entire line segment lies on the planes' intersection, making any internal ratio k∈(0,∞)k \in (0, \infty) valid.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterIntroduction to Three-dimensional Geometry - Class 11
ConceptRatio of Division (k:1)
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree