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Question #40861

Difficulty: 8/10 | 🟢 Free

The Question

Let P(x,y,z)P(x, y, z) be a point in R3\mathbb{R}^3. Define two complex numbers associated with PP as: w1=(2x+y)+i(y+z)w_1 = (2x + y) + i(y + z) w2=(2x−y)+i(y−z)w_2 = (2x - y) + i(y - z) Let SS be the locus of points PP such that ∣w1∣2+∣w2∣2=16|w_1|^2 + |w_2|^2 = 16 and w1w2ˉ+w1ˉw2=0w_1 \bar{w_2} + \bar{w_1} w_2 = 0. Find the maximum distance between any two points on the locus SS.

Options

  • A.

    424\sqrt{2}

  • B.

    252\sqrt{5}

  • C.

    44

  • D.

    88

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

Locus via Distance Constraints|Geometrical Interpretation of Modulus|Locus Problems via Transformation

Why This Question Is Tricky

Common Mistakes

This question tests the isomorphism between complex moduli constraints and 3D Euclidean geometry.

The primary trap lies in the coordinate transformation: students often assume that a constraint like ∣w1∣2+∣w2∣2=k|w_1|^2 + |w_2|^2 = k maps to a sphere, failing to account for the non-orthogonal scaling in the transformation which distorts the locus into an ellipsoid.

Furthermore, even if they correctly identify the ellipsoid 4x2+2y2+z2=84x^2 + 2y^2 + z^2 = 8, they might ignore the second orthogonality condition or incorrectly assume the maximum distance lies along the major axis of the ellipsoid (424\sqrt{2}).

The true locus is restricted to planar slices (z=±2xz = \pm 2x), altering the maximum distance to 252\sqrt{5}.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterIntroduction to Three-dimensional Geometry - Class 11
ConceptLocus via Distance Constraints
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree