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Question #40833

Difficulty: 8/10 | 🟢 Free

The Question

Let MM be the 3×33 \times 3 symmetric matrix representing the rectangular hyperbola H:x2−y2+4xy+6x−8y+K=0H: x^2 - y^2 + 4xy + 6x - 8y + K = 0. A new matrix NN is obtained by applying the elementary row operation R3→R3+4R1−2R2R_3 \to R_3 + 4R_1 - 2R_2 to MM. If the conic represented by the equation (xy1)N(xy1)=0\begin{pmatrix} x & y & 1 \end{pmatrix} N \begin{pmatrix} x \\ y \\ 1 \end{pmatrix} = 0 degenerates into a pair of straight lines, then the value of KK is:

Options

  • A.

    −16-16

  • B.

    −12-12

  • C.

    44

  • D.

    1616

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

Rectangular Hyperbola|Elementary Row Operations|Singular vs. Non-Singular Threshold

Why This Question Is Tricky

Common Mistakes

This question tests the structural understanding of conics via linear algebra.

The primary trap lies in the asymmetric nature of matrix NN after row operations.

Students often incorrectly assume det⁡(N)=0\det(N) = 0 directly dictates degeneracy, forgetting that a quadratic form is governed strictly by the symmetric part of its matrix representation, Nsym=N+NT2N_{sym} = \frac{N+N^T}{2}.

By forcing the expansion of XTNX=0X^T N X = 0, the student must extract the new coefficients and evaluate the singular threshold (determinant of the new symmetric matrix) to find KK.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterConic Sections - Class 11
ConceptRectangular Hyperbola
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree