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Question #40816

Difficulty: 8/10 | 🟢 Free

The Question

Let Γ\Gamma be a family of curves in the first quadrant of the xyxy-plane. For any point P(x,y)P(x,y) on a curve in Γ\Gamma, consider the conic CPC_P given by the equation X2+yxXY+Y2=1X^2 + \frac{y}{x} X Y + Y^2 = 1 in the XYXY-plane. The polar of P(x,y)P(x,y) with respect to CPC_P is identical to the tangent line to the orthogonal trajectory of Γ\Gamma passing through PP. If the curve in Γ\Gamma passes through the point (2,1)(\sqrt{2}, 1), then the value of y2y^2 when x=23x = 2\sqrt{3} is:

Options

  • A.

    4

  • B.

    6

  • C.

    8

  • D.

    10

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

Polar and Pole Duality|Orthogonal Trajectories|Tangent/Normal Slope Interplay

Why This Question Is Tricky

Common Mistakes

This question tests the interplay between pole-polar duality and orthogonal trajectories, specifically targeting slope relationships.

The primary trap lies in the interpretation of 'identical to the tangent line to the orthogonal trajectory'.

Students often mistakenly equate the slope of the polar directly to the slope of the curve Γ\Gamma (dy/dx=mpolardy/dx = m_{polar}), or apply the negative reciprocal incorrectly, forgetting that the orthogonal trajectory's tangent already incorporates the −1/m-1/m condition.

This leads to an incorrect homogeneous differential equation.

Furthermore, the problem requires setting up a parameter-dependent conic CPC_P and correctly applying the polar equation T=0T=0 with current coordinates, filtering out candidates who lack rigorous algebraic control.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterConic Sections - Class 11
ConceptPolar and Pole Duality
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree