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Question #40811

Difficulty: 8/10 | 🟢 Free

The Question

A family of conics CλC_\lambda is defined by the matrix equation XTMλX=0X^T M_\lambda X = 0, where X=(xy1)X = \begin{pmatrix} x \\ y \\ 1 \end{pmatrix} and Mλ=(λ101λ000−1)M_\lambda = \begin{pmatrix} \lambda & 1 & 0 \\ 1 & \lambda & 0 \\ 0 & 0 & -1 \end{pmatrix} The condition that a line lx+my+n=0lx + my + n = 0 is tangent to CλC_\lambda is given by the vanishing of the bordered determinant: Δ(λ)=∣λ10l1λ0m00−1nlmn0∣=0\Delta(\lambda) = \begin{vmatrix} \lambda & 1 & 0 & l \\ 1 & \lambda & 0 & m \\ 0 & 0 & -1 & n \\ l & m & n & 0 \end{vmatrix} = 0 A student simplifies Δ(λ)\Delta(\lambda) by performing the elementary row operation R1→λR1−R2R_1 \to \lambda R_1 - R_2, yielding a new determinant Δ′(λ)\Delta'(\lambda). The student incorrectly assumes Δ′(λ)=0\Delta'(\lambda) = 0 is the exact condition of tangency for all λ∈R\lambda \in \mathbb{R}. Consequently, the student finds a specific value λ0∈R\lambda_0 \in \mathbb{R} for which Δ′(λ0)=0\Delta'(\lambda_0) = 0 identically for all l,m,nl, m, n, falsely concluding that every line in the plane is tangent to Cλ0C_{\lambda_0}. Find the equation of the true director circle of the conic Cλ0C_{\lambda_0}.

Options

  • A.

    x2+y2=0x^2 + y^2 = 0

  • B.

    x2+y2=12x^2 + y^2 = \frac{1}{2}

  • C.

    x2+y2=1x^2 + y^2 = 1

  • D.

    x2+y2=2x^2 + y^2 = 2

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Correct Answer

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Explanation

How the Examiner Thinks

Specialist

Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.

Concepts Behind This Question

Condition of Tangency|Director Circle Locus|Elementary Row Operation Invariance

Why This Question Is Tricky

Common Mistakes

This question tests the student's rigorous understanding of determinant properties and the condition of tangency.

The core trap lies in the invariance of elementary row operations: while adding a multiple of one row to another preserves the determinant, multiplying a row by a parameter λ\lambda scales the entire determinant by λ\lambda.

Students who algorithmically apply row operations without tracking this scalar will introduce an extraneous root (λ=0\lambda = 0).

This leads them to a singular matrix scenario where the tangency condition trivially vanishes, falsely implying universal tangency.

Recognizing this algebraic trap forces the student to identify the true conic at λ=0\lambda = 0 (a rectangular hyperbola) and correctly compute its director circle, which degenerates to a point.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterConic Sections - Class 11
ConceptCondition of Tangency
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree