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Question #40796

Difficulty: 8/10 | 🟢 Free

The Question

Let SS be the set of all continuous functions f:[1,3]→Rf: [1, 3] \to \mathbb{R} satisfying f(x)≥∣∫xx2−4x+5(t−2) dt∣f(x) \ge \left| \int_{x}^{x^2-4x+5} (t-2) \, dt \right| for all x∈[1,3]x \in [1, 3]. The minimum possible value of the definite integral ∫13f(x) dx\int_{1}^{3} f(x) \, dx is:

Options

  • A.

    15\frac{1}{5}

  • B.

    25\frac{2}{5}

  • C.

    35\frac{3}{5}

  • D.

    45\frac{4}{5}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

Parabola Shifted Vertex|Substitution (Change of Variable)|Compound Function Boundaries|Inequalities in Definite Integrals

Why This Question Is Tricky

Common Mistakes

This question tests the evaluation of definite integrals involving absolute values and compound parabolic boundaries, a common setup for integral inequalities.

The trap lies in the substitution u=x−2u = x-2, which shifts the coordinate system.

Students frequently fail to identify the internal roots of the resulting polynomial u4−3u2+1u^4 - 3u^2 + 1 within the integration interval [0,1][0, 1].

By ignoring the sign change at u=(5−1)/2u = (\sqrt{5}-1)/2, they incorrectly compute the net area (yielding 1/51/5) instead of the absolute area required by the inequality bound, missing the correct answer of 3/53/5.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterConic Sections - Class 11
ConceptParabola Shifted Vertex
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree