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Question #40783

Difficulty: 8/10 | 🟢 Free

The Question

For a parameter α∈[0,2π)\alpha \in [0, 2\pi), a family of lines is given by xcos⁡α+ysin⁡α=kcos⁡2αx \cos \alpha + y \sin \alpha = k \cos 2\alpha, where k>0k > 0 is a constant. Let CkC_k be the envelope of this family of lines. As kk varies over all positive real numbers, a family of curves F={Ck:k>0}\mathcal{F} = \{C_k : k > 0\} is generated. Which of the following represents the orthogonal trajectories of the family F\mathcal{F}?

Options

  • A.

    (x−y)4/3−(x+y)4/3=c(x-y)^{4/3} - (x+y)^{4/3} = c

  • B.

    (x−y)4/3+(x+y)4/3=c(x-y)^{4/3} + (x+y)^{4/3} = c

  • C.

    (x−y)2/3−(x+y)2/3=c(x-y)^{2/3} - (x+y)^{2/3} = c

  • D.

    (x+y)4/3+(x−y)2/3=c(x+y)^{4/3} + (x-y)^{2/3} = c

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Monster

Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.

Concepts Behind This Question

Normal Form Parameters|Geometric Interpretation|Orthogonal Trajectories

Why This Question Is Tricky

Common Mistakes

This problem tests the geometric interpretation of the normal form and the envelope of a family of lines, combined with orthogonal trajectories.

The primary trap lies in the algebraic complexity of the envelope; students who fail to recognize the symmetry and apply a π/4\pi/4 coordinate rotation will face an unintegrable differential equation in the standard xyxy-plane.

Furthermore, a common conceptual error is attempting to find the orthogonal trajectories of the lines themselves for a fixed kk, rather than the envelope family F\mathcal{F} generated by varying kk, which leads to incorrect slope substitutions and sign errors.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterStraight Lines - Class 11
ConceptNormal Form Parameters
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree