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Question #40779

Difficulty: 8/10 | 🟢 Free

The Question

Four distinct collinear points P1,P2,P3,P4P_1, P_2, P_3, P_4 lie on the curve C:y=(x2−6x+5)2/3+2xC: y = (x^2 - 6x + 5)^{2/3} + 2x and the line L:y=2x+1L: y = 2x + 1. Let their xx-coordinates be x1<x2<x3<x4x_1 < x_2 < x_3 < x_4. Let NN be the number of points on CC with xx-coordinate in the interval (x1,x4)(x_1, x_4) at which the tangent to CC is parallel to LL. Find the value of NN.

Options

  • A.

    1

  • B.

    2

  • C.

    3

  • D.

    4

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

Condition of Collinearity|Critical Point vs Stationary Point|Rolle's Theorem Anchors

Why This Question Is Tricky

Common Mistakes

This question tests the precise conditions required for Rolle's Theorem and the Mean Value Theorem.

Students often blindly apply the theorem, assuming that a line intersecting a curve at four distinct collinear points guarantees at least three points where the tangent is parallel to the secant line (roots of the derivative).

The trap lies in the non-differentiability of the function at x=1x=1 and x=5x=5, which fall exactly inside the outer intervals (x1,x2)(x_1, x_2) and (x3,x4)(x_3, x_4).

Because differentiability fails at these critical points, the derivative does not vanish in those intervals, reducing the actual number of parallel tangents from the erroneously expected 3 down to just 1.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterStraight Lines - Class 11
ConceptCondition of Collinearity
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree