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Question #40710

Difficulty: 8/10 | 🟢 Free

The Question

Let αn\alpha_n and βn\beta_n be the roots of the quadratic equation x2−nx+1=0x^2 - n x + 1 = 0. For each integer n≥0n \ge 0, define the matrix An=(αn+βnαnβnαnαn+βnβnβnαnαn+βn)A_n = \begin{pmatrix} \alpha_n + \beta_n & \alpha_n & \beta_n \\ \alpha_n & \alpha_n + \beta_n & \beta_n \\ \beta_n & \alpha_n & \alpha_n + \beta_n \end{pmatrix} Find the value of ∑n=010det⁡(adj(An)+I)\sum_{n=0}^{10} \det(\text{adj}(A_n) + I) where II is the 3×33 \times 3 identity matrix.

Options

  • A.

    4642

  • B.

    4640

  • C.

    4641

  • D.

    4620

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

Quadratic Roots in Sequences|Adjoint-Determinant Relationship|Singular vs Non-Singular Matrices

Why This Question Is Tricky

Common Mistakes

This question tests the spectral properties of the adjoint matrix, specifically targeting the trap where students incorrectly assume adj(A)=∣A∣A−1\text{adj}(A) = |A|A^{-1}.

For n=0n=0, the matrix A0A_0 is singular (∣A0∣=0|A_0|=0), making A0−1A_0^{-1} undefined.

Students relying on the inverse formula will either skip the n=0n=0 term (yielding 4640) or incorrectly assume adj(A0)\text{adj}(A_0) is the zero matrix (yielding 4641).

The rigorous approach requires recognizing that the eigenvalues of adj(A)\text{adj}(A) are the products of pairs of eigenvalues of AA, a property that holds continuously even when the matrix is singular.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterSequences and Series - Class 11
ConceptQuadratic Roots in Sequences
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree