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Question #40681

Difficulty: 8/10 | 🟢 Free

The Question

Let f(x)=x2−4f(x) = x^2 - 4 and g(x)=∣x−3∣−4g(x) = |x-3| - 4 for all x∈Rx \in \mathbb{R}. Define H(x)=f(g(x))H(x) = f(g(x)). Let SS be the set of all real numbers xx such that H′(x)=0H'(x) = 0, and DD be the set of all real numbers xx such that H(x)H(x) is not differentiable. If α=∑x∈Sx\alpha = \sum_{x \in S} x, β=n(S)\beta = n(S), and γ=n(D)\gamma = n(D), where n(A)n(A) denotes the number of elements in set AA, find the value of α2+β2+γ2\alpha^2 + \beta^2 + \gamma^2.

Options

  • A.

    41

  • B.

    49

  • C.

    90

  • D.

    91

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Monster

Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.

Concepts Behind This Question

Selection of AP Terms|Rolle's Theorem Anchors|Chain Rule Inner Function Differentiability

Why This Question Is Tricky

Common Mistakes

This question tests the limits of Rolle's Theorem on composite functions with absolute values.

The roots of H(x)=0H(x) = 0 are {−3,1,5,9}\{-3, 1, 5, 9\}, forming an Arithmetic Progression.

A common trap is blindly applying Rolle's Theorem to assume H′(x)=0H'(x) = 0 has roots in every interval between these zeros, leading to the false conclusion that S={−1,3,7}S = \{-1, 3, 7\}.

However, Rolle's Theorem requires differentiability on the open interval.

Here, H(x)H(x) has a cusp at x=3x=3 (exactly inside the interval (1,5)(1, 5)), meaning the derivative never vanishes there.

Students who rely on memorized AP patterns for derivatives of polynomials will fail to verify the domain of differentiability, incorrectly inflating the size of set SS and missing the non-differentiable point DD.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterSequences and Series - Class 11
ConceptSelection of AP Terms
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree