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Question #40669

Difficulty: 8/10 | 🟢 Free

The Question

Let f(x)=∫π/6x(252sin⁡2t+2csc⁡2t)dtf(x) = \int_{\pi/6}^{x} \left( \frac{25}{2}\sin^2 t + 2\csc^2 t \right) dt for x∈(0,π/2)x \in (0, \pi/2). If m0m_0 is the minimum possible slope of the tangent to the curve y=f(x)y = f(x), find the value of sin⁡−1(sin⁡m0)+cos⁡−1(cos⁡m0)\sin^{-1}(\sin m_0) + \cos^{-1}(\cos m_0).

Options

  • A.

    7π−207\pi - 20

  • B.

    π\pi

  • C.

    20−7π20 - 7\pi

  • D.

    10−3π10 - 3\pi

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Monster

Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.

Concepts Behind This Question

Arithmetic Mean Inequality|Tangent/Normal Slope Interplay|Composition Inverse Identity Traps

Why This Question Is Tricky

Common Mistakes

This question integrates calculus, the AM-GM inequality, and inverse trigonometric functions.

The primary trap is the 'Composition Inverse Identity Trap', where students mechanically assume sin⁡−1(sin⁡x)=x\sin^{-1}(\sin x) = x and cos⁡−1(cos⁡x)=x\cos^{-1}(\cos x) = x, ignoring the principal value branch restrictions ([−π/2,π/2][-\pi/2, \pi/2] for sine and [0,π][0, \pi] for cosine).

By forcing the minimum slope to be 1010 (a radian measure outside the principal domains), students who fail to reduce 1010 to its correct reference angles (3π−103\pi - 10 and 4π−104\pi - 10) will arrive at incorrect linear combinations of π\pi.

This penalizes formula-hunting without strict domain verification.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterSequences and Series - Class 11
ConceptArithmetic Mean Inequality
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree