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Question #40646

Difficulty: 8/10 | 🟢 Free

The Question

A biased 3-sided die with faces labeled A,B,A, B, and CC is rolled 6 times. The probabilities of landing on A,B,A, B, and CC on any given roll are 12,14,\frac{1}{2}, \frac{1}{4}, and 14\frac{1}{4} respectively. Let EE be the event that every face appears at least once during the 6 rolls. If XX is the random variable representing the number of times face AA appears, find the conditional expectation E[X∣E]E[X \mid E].

Options

  • A.

    5722\frac{57}{22}

  • B.

    3

  • C.

    380143\frac{380}{143}

  • D.

    52\frac{5}{2}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Specialist

Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.

Concepts Behind This Question

Multinomial Theorem|Random Variable Expectation|Complementary Counting

Why This Question Is Tricky

Common Mistakes

This question tests the calculation of conditional expectation within a multinomial distribution framework.

The primary trap is the 'Complementary Counting' hurdle: students often miscalculate the sample space P(E)P(E) by treating the constraints as independent binomial events, or they attempt to find the conditional distribution of XX directly, leading to intractable algebraic sums.

The elegant, JEE-Advanced level bypass requires using the linearity of expectation with indicator variables (E[X⋅IE]E[X \cdot \mathbb{I}_E]).

Recognizing that E[X⋅IB=0]=E[X∣B=0]P(B=0)E[X \cdot \mathbb{I}_{B=0}] = E[X|B=0]P(B=0) and that terms where A=0A=0 trivially zero out the expectation is the key to avoiding the lethal collision of dependent variable states.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterBinomial Theorem - Class 11
ConceptMultinomial Theorem
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree