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Question #40645

Difficulty: 8/10 | 🟢 Free

The Question

Let an(x)a_n(x) be the coefficient of tnt^n in the expansion of (1+t+x∣x∣t2)n\left(1 + t + \frac{x}{|x|} t^2\right)^n for x≠0x \neq 0. Let DD be the set of all x∈R∖{0}x \in \mathbb{R} \setminus \{0\} for which the series ∑n=1∞an(x)xn\sum_{n=1}^{\infty} a_n(x) x^n converges absolutely. If D=(−a,0)∪(0,b)D = (-a, 0) \cup (0, b), find the value of 1a2+1b2\frac{1}{a^2} + \frac{1}{b^2}.

Options

  • A.

    10

  • B.

    12

  • C.

    14

  • D.

    16

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Specialist

Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.

Concepts Behind This Question

Multinomial Theorem|Modulus Sign Dependency|Real-Valued Function Domain

Why This Question Is Tricky

Common Mistakes

This question tests the convergence of a multinomial series where the base depends on the sign of the variable.

The trap lies in assuming the radius of convergence is symmetric or determined purely by real roots.

For x<0x < 0, the alternating signs in the multinomial expansion cause massive cancellation, leading to a complex singularity that dictates the radius of convergence.

Students failing to account for the modulus split or the complex roots of the discriminant will incorrectly evaluate the domain.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterBinomial Theorem - Class 11
ConceptMultinomial Theorem
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree