Start Learning Free

Before You Begin

Question #40622

Difficulty: 8/10 | 🟢 Free

The Question

Let x=∑k=1∞96kx = \sum_{k=1}^\infty \frac{9}{6^k} and y=∑k=1∞15ky = \sum_{k=1}^\infty \frac{1}{5^k}. Define Sm=∑n=1m∑r=1n(nr)xrynS_m = \sum_{n=1}^m \sum_{r=1}^n \binom{n}{r} x^r y^n. Find the value of L1+L2L_1 + L_2, where L1=lim⁡m→∞[Sm]L_1 = \lim_{m \to \infty} [S_m] and L2=[lim⁡m→∞Sm]L_2 = \left[ \lim_{m \to \infty} S_m \right], and [⋅][ \cdot ] denotes the greatest integer function.

Options

  • A.

    2

  • B.

    3

  • C.

    4

  • D.

    5

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

Binomial Coefficient Summation Properties|Infinite GP Convergence|Greatest Integer Function (GIF)

Why This Question Is Tricky

Common Mistakes

This question tests the critical distinction between the limit of a greatest integer function (GIF) and the GIF of a limit, specifically when a series converges to an integer from below.

Students often incorrectly assume that lim⁡[Sm]=[lim⁡Sm]\lim [S_m] = [\lim S_m].

By embedding the sequence within a modulated binomial-geometric sum, the problem forces students to first evaluate the exact finite sum SmS_m.

The 'lethal collision' occurs at the boundary: because the subtractive error term is strictly positive, SmS_m approaches 2 strictly from below (Sm→2−S_m \to 2^-).

Consequently, the sequence of GIFs stabilizes at 1, yielding L1=1L_1 = 1, whereas the GIF of the continuous limit is [2]=2[2] = 2.

Failing to analyze the sign of the remainder term leads to the trap answer of 4.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterBinomial Theorem - Class 11
ConceptBinomial Coefficient Summation Properties
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree