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Question #40599
The Question
Let be the number of ways to select 4 items from a collection of 3 identical apples, 4 identical oranges, and 5 identical bananas. Let be a plane with normal vector , where and . The plane satisfies the equation . Let be the line , and let be the orthogonal projection of the line onto the plane . If is the line , find the shortest distance between the lines and .
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Specialist
Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.
Concepts Behind This Question
Selection from Identical Items|Scalar Triple Product Volume Logic|Orthogonal projection of a line|Shortest distance between skew lines
Why This Question Is Tricky
Common Mistakes
This question fuses combinatorics with 3D vector geometry to create a multi-layered trap.
The first filter requires students to correctly apply the principle of inclusion-exclusion or generating functions to find the selection count , which acts as the scalar distance for the plane.
The primary geometric trap lies in finding the orthogonal projection of a line onto a plane.
Students often erroneously project the direction vector instead of recognizing that the line is parallel to the plane, requiring an affine shift of a point on the line.
A sign error in the projection formula or mistakenly using the plane's normal for the shortest distance calculation will lead to the distractor options.
Quick Facts About This Question
Question Information
| Subject | Mathematics |
| Chapter | Permutations and Combinations - Class 11 |
| Concept | Selection from Identical Items |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |