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Question #40582
The Question
Let and . Find the number of integer solutions to the equation such that for all .
Options
- A.
600
- B.
680
- C.
540
- D.
80
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Bridge
Practice problems that bridge the gap between foundational theory and advanced practical application.
Concepts Behind This Question
Distributing Identical Items (Stars and Bars)|Method of Differences|Square Root and Modulus Logic
Why This Question Is Tricky
Common Mistakes
This question tests the synthesis of telescoping series (Method of Differences) with constrained integer partitions.
The primary trap lies in the Modulus Gatekeeper ().
Students often correctly shift the variables to non-negative integers () but forget to enforce the new upper bound (), erroneously calculating the unconstrained Stars and Bars result .
Furthermore, the problem rewards advanced algebraic symmetry; recognizing that finding the coefficient of is identical to finding the coefficient of significantly reduces the Inclusion-Exclusion Principle (IEP) computational burden.
Quick Facts About This Question
Question Information
| Subject | Mathematics |
| Chapter | Permutations and Combinations - Class 11 |
| Concept | Distributing Identical Items (Stars and Bars) |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |